Latihan Soal 2 Jaringan Komputer

Nama                           : Febri Haryanti

Nim                             : 12191122

Kelas                           : 12.4A.04

Mata Kuliah                : Jaringan Komputer

Dosen Pengampu        : Syafrianto, M.Kom

Pertemuan                   : 2

 

Latihan Soal 2

 

Soal

Hitunglah jumlah Network dan Host yang terbentuk dalam alamt IP Address di bawah ini :

1.      192.168.10.1        /30

2.      172.168.10.1        /16

3.      172.168.10           /16

4.      10.168.5.1            /8

5.      10.168. 5.1           /17

 

Jawaban

1.      192.168.10.1        /30

IP Addres                        : 192.168.10.1

Class IP                            : C

Subnet default                 : 255.255.255.0           /30

Subnet yang ditentukan   : 255.255.255.252       /30

Binary                              : 11111111. 11111111. 11111111. 1111100

Network                           = 2n

                                         = 26

                                         = 64 Network

Host                                 = 2h  - 2

                                         = 22 – 2

                                         = 2 Host

2.      172.168.10.1        /16

IP Addres                        : 172.168.10.1

Class IP                            : C

Subnet default                 : 255.255.0.0   /16

Subnet yang ditentukan   : 255.255.0.0   /16

Binary                              : 11111111. 11111111. 00000000. 00000000

Network                           = 2n

                                         = 20

                                         = 1 Network

Host                                 = 2h  - 2

                                         = 216 – 2

                                         = 65.534 Host

  

3.      172.168.10           /22

IP Addres                        : 172.168.10.1

Class IP                            : B

Subnet default                 : 255.255.0.0               /22

Subnet yang ditentukan   : 255.255.252.0           /22

Binary                              : 11111111. 11111111. 11111100. 00000000

Network                           = 2n

                                         = 26

                                         = 64 Network

Host                                 = 2h  - 2

                                         = 210 – 2

                                         = 1.022 Host


4.      10.168.5.1                        /8

IP Addres                        : 10.168.5.1

Class IP                            : A

Subnet default                 : 255.0.0          /8

Subnet yang ditentukan   : 255.0.0          /8

Binary                              : 11111111. 00000000. 00000000. 00000000

Network                           = 2n

                                         = 20

                                         = 1 Network

Host                                 = 2h  - 2

                                         = 224 – 2

                                         = 16.777.214 Host


5.      10.168.5.1                        /17

IP Addres                        : 10.168.5.1

Class IP                            : A

Subnet default                 : 255.0.0                      /17

Subnet yang ditentukan   : 255.255.128.0           /17

Binary                              : 11111111. 11111111. 10000000. 00000000

Network                           = 2n

                                         = 29

                                         = 512 Network

Host                                 = 2h  - 2

                                         = 215 – 2

                                         = 32.766 Host



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